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2 Litres of mercury at 80 degree celsius is pushed into a plastic bucket containing 10 litres of mercury at temprature T. If the final temperature of the mixture is 30 degree celsius. What is the value of T?

```
9 years ago

## Answers : (1)

105 Points
```							Dear vikas,
the heat lost by 80 degree mercury is taken by mercury at T degrees
using
M1Cp (80-30) = M2Cp (T-30)
density *volume *(50) = Density * volume (T-30)
2 *50 = 10 * (T-30)
=> 10 = T -30
=> T = 40 degrees
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```
9 years ago
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