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2 Litres of mercury at 80 degree celsius is pushed into a plastic bucket containing 10 litres of mercury at temprature T. If the final temperature of the mixture is 30 degree celsius. What is the value of T?

2 Litres of mercury at 80 degree celsius is pushed into a plastic bucket containing 10 litres of mercury at temprature T. If the final temperature of the mixture is 30 degree celsius. What is the value of T?

Grade:12th Pass

1 Answers

suryakanth AskiitiansExpert-IITB
105 Points
10 years ago

Dear vikas,

the heat lost by 80 degree mercury is taken by mercury at T degrees

using

M1Cp (80-30) = M2Cp (T-30)

density *volume *(50) = Density * volume (T-30)

2 *50 = 10 * (T-30)

=> 10 = T -30

=> T = 40 degrees

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