Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Vikas TU Grade: 12th Pass

2 Litres of mercury at 80 degree celsius is pushed into a plastic bucket containing 10 litres of mercury at temprature T. If the final temperature of the mixture is 30 degree celsius. What is the value of T?

7 years ago

Answers : (1)

suryakanth AskiitiansExpert-IITB
105 Points

Dear vikas,

the heat lost by 80 degree mercury is taken by mercury at T degrees


M1Cp (80-30) = M2Cp (T-30)

density *volume *(50) = Density * volume (T-30)

2 *50 = 10 * (T-30)

=> 10 = T -30

=> T = 40 degrees

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..


Askiitians Expert

Suryakanth –IITB

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
  • Kinematics & Rotational Motion
  • OFFERED PRICE: Rs. 636
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details