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Grade: 11
        

Acc to archimedes principle, loss of weight of a body in a liquid is equal to the wt of the liquid displaced


i.e. W2 -W1 = Vpg


But I read the synopsis in one of the books that when a body is dipped in a liqid, then it's wt in fluid  = Vpg.


Which of the two is right?


Also Vag(1-p/a) = what ?  Is it the change in fluid or the wt of the fluid in the liquid. here a= density of the body


 p = density of the liquid.


What is the apparent weight of the body numericlly equal to?


I got confused due to reading contradictory statements in different books. Please help me solve this dilemma.

7 years ago

Answers : (1)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
							

Dear Deeksha

Please refer the image

All the best.                                                           

AKASH GOYAL

AskiitiansExpert-IITD

 

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7 years ago
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