when t = 0, a particle at (1,0,0) moves towards (4,4,12) with a constant velocity of magnitude of 65 m/s. the position of the particle is measured in meters and time in sec. Assuming constant velocity the position of the particle at t= 2 sec is –(a) (13i– 120j +40k) m(b) (40i +31j– 120k) m(c) (13i – 40j+ 12k) m(d) (31i + 40j+ 120k) m

Dear sahil,

The correct answer is c)

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