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Neel Pratik Bhatt Grade: 9

A bullet of mass 10grms is travelling horizontally with a velocity of 150 m/sec strikes a stationary wooden block and comes to arest after 0.03 seconds. Calculate the distance of prnitration of the bullet into the wooden block.

please help!


7 years ago

Answers : (2)

Radhika Batra
247 Points

Dear neel,

Given that :

Initial velocity (u) = 150 m/s.

Final velocity (v)  =  0 m/s.

Time taken for the body to come at rest (t)= 0.03 sec.

Now according to newton's first law:

 v = u - at   -------------------------------------------  eq 1.

so from this equation value of :  a = (u/t).

Now from the euation we have :

s = ut - 1/2at2 ----------------------------------------- eq 2.

put the values of u, t, a in the 2nd equation.

after solving we will get that :

s = 4.5m.

Thus the bullet will  penetrate 4.5 meters inside the wodden block. provides online iit jee courses and IIT JEE Test Series with IITians. Click here to get free online test series and check your status timely or you can join us as our registered user for getting best iit jee study material or iit jee test series.

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all the best.

thanks and regards.

7 years ago
sidharth G
18 Points

mass of bullet = 0.01 kg

initial vel ,u = 150 m/s

final vel , v= 0

time= 0.03s

distance = s



use these eq to find a(accelaration) and s respectively .u will get the answer


7 years ago
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