# A bullet of mass 10grms is travelling horizontally with a velocity of 150 m/sec strikes a stationary wooden block and comes to arest after 0.03 seconds. Calculate the distance of prnitration of the bullet into the wooden block.please help!

247 Points
14 years ago

Dear neel,

Given that :

Initial velocity (u) = 150 m/s.

Final velocity (v)  =  0 m/s.

Time taken for the body to come at rest (t)= 0.03 sec.

Now according to newton's first law:

v = u - at   -------------------------------------------  eq 1.

so from this equation value of :  a = (u/t).

Now from the euation we have :

s = ut - 1/2at2 ----------------------------------------- eq 2.

put the values of u, t, a in the 2nd equation.

after solving we will get that :

s = 4.5m.

Thus the bullet will  penetrate 4.5 meters inside the wodden block.

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sidharth G
18 Points
13 years ago

mass of bullet = 0.01 kg

initial vel ,u = 150 m/s

final vel , v= 0

time= 0.03s

distance = s

## v2=u2+2as

use these eq to find a(accelaration) and s respectively .u will get the answer