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A bullet of mass 10grms is travelling horizontally with a velocity of 150 m/sec strikes a stationary wooden block and comes to arest after 0.03 seconds. Calculate the distance of prnitration of the bullet into the wooden block.
please help!
Dear neel,
Given that :
Initial velocity (u) = 150 m/s.
Final velocity (v) = 0 m/s.
Time taken for the body to come at rest (t)= 0.03 sec.
Now according to newton's first law:
v = u - at ------------------------------------------- eq 1.
so from this equation value of : a = (u/t).
Now from the euation we have :
s = ut - 1/2at2 ----------------------------------------- eq 2.
put the values of u, t, a in the 2nd equation.
after solving we will get that :
s = 4.5m.
Thus the bullet will penetrate 4.5 meters inside the wodden block.
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thanks and regards.
mass of bullet = 0.01 kg
initial vel ,u = 150 m/s
final vel , v= 0
time= 0.03s
distance = s
use these eq to find a(accelaration) and s respectively .u will get the answer
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