The upper end of wire 1 m long and 2 mm radius is clamped. The lower end is twisted through an angle of 45°. The angle of shear is

(a) 0.09° (b) 0.9°
(c) 9° (d) 90°

Question

The upper end of wire 1 m long and 2 mm radius is clamped. The lower end is twisted through an angle of 45°. The angle of shear is (a) 0.09° (b) 0.9° (c) 9° (d) 90°

Saurabh Koranglekar · Answer

Vikas TU · Answer

Dear student The above ans is missing Phi = rQ/L = 0.012 degree Hope this will help Good Luck Cheers …..........................

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The upper end of wire 1 m long and 2 mm radius is clamped. The lower end is twisted through an angle of 45°. The angle of shear is (a) 0.09° (b) 0.9° (c) 9° (d) 90°

The upper end of wire 1 m long and 2 mm radius is clamped. The lower end is twisted through an angle of 45°. The angle of shear is

(a) 0.09° (b) 0.9°
(c) 9° (d) 90°

2 Answers

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The upper end of wire 1 m long and 2 mm radius is clamped. The lower end is twisted through an angle of 45°. The angle of shear is (a) 0.09° (b) 0.9° (c) 9° (d) 90°

The upper end of wire 1 m long and 2 mm radius is clamped. The lower end is twisted through an angle of 45°. The angle of shear is (a) 0.09° (b) 0.9° (c) 9° (d) 90°

2 Answers

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The upper end of wire 1 m long and 2 mm radius is clamped. The lower end is twisted through an angle of 45°. The angle of shear is

(a) 0.09° (b) 0.9°
(c) 9° (d) 90°