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The radius of the first orbit of the electron in a hydrogen atom is 5.3 x 10-11 m; then the radius of the second orbit must be A. 15.9 x 10^-11 m B. 10.6 x 10 m C. 21.2 x 10^-11 m D. 42.4 x 10^-11 m

The radius of the first orbit of the electron in a hydrogen atom is 5.3 x 10-11 m; then the radius of the second orbit must be
A. 15.9 x 10^-11 m
B. 10.6 x 10 m
C. 21.2 x 10^-11 m
D. 42.4 x 10^-11 m

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2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
The radius of the innermost orbit of a hydrogen atom, r1= 5.3 × 10−11m.

Let r2be the radius of the orbit at n = 2. It is related to the radius of the innermost orbit as:

r2= (n)2r1

= 4 x 5.3 x 10-11= 2.12 x 10-10m
Vikas TU
14149 Points
3 years ago
As radius is directly proportional to n^2 ( n is orbit)
So for 2 nd orbit its 2^2 × 5.3× 10°-11
4× 5.3× 10^-11
21.2 × 10^ -11

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