An object moving with the speed of 6.25m/s, is decelerated at a rate given by:dv–2.5vdt?where v is the instantaneous speed. The time taken by the object, to come to rest would be?

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Saurabh Koranglekar · Answer

Vikas TU · Answer

An object moving with a speed of 6.25 m/s is decelerated at a constant rate of a= - 2.5*v^1/2, where v is the instantaneous speed. find the time taken by the object to come to rest. answer is 7.905

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An object moving with the speed of 6.25m/s, is decelerated at a rate given by:dv–2.5vdt?where v is the instantaneous speed. The time taken by the object, to come to rest would be?

An object moving with the speed of 6.25m/s, is decelerated at a rate given by:dv–2.5vdt?where v is the instantaneous speed. The time taken by the object, to come to rest would be?

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An object moving with the speed of 6.25m/s, is decelerated at a rate given by:dv–2.5vdt?where v is the instantaneous speed. The time taken by the object, to come to rest would be?

An object moving with the speed of 6.25m/s, is decelerated at a rate given by:dv–2.5vdt?where v is the instantaneous speed. The time taken by the object, to come to rest would be?

2 Answers

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Other Related Questions on Engineering Entrance Exams

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