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A 700pf of capacitor is charged by 50v battery. The electrostatic energy stored in it is
It is given that :Charge on a capacitor, C=700\ pF=700* 10-¹²Potential, V=50VEnergy stored in a capacitor is given by the following relation :U=½CV²C is capacitance of a circuit.V is the potential difference.U=½700*10-¹²(50)²U=8.75*10^-7
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