Vikas TU
Last Activity: 4 Years ago
As per the question,
Given data:
A wire under tension vibrates with a frequency = 450 hertz
According to the speed of the string, we have
v = sqrt[(T-l)/m]
Let V₁ = 450 Hz
Now,
The wire were half as long twice as thick and under one-fourth tention:
New length = l/4
m = 2m
V1 = sqrt[(T-l)/m]
And
V2 = sqrt[(T-l)/2m-4]
Divide V₂ by V₁, we get
∴ v₂ = 159.12 Hz
Hence, the fundamental frequency = 159.12 Hz