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Two positively charged particles of charges q1 and q2 have mass m each. A uniform electric field having magnitude E exists in positive x direction as shown in figure. The given two charged particles are released from rest at t=0 as shown in figure. If position of q1 at t=2 s is given by coordinate (+2a,0) then the x coordinate of q2 at t=2s is (neglect gravitational interaction between the particles) -

Two positively charged particles of charges q1 and q2 have mass m each. A uniform electric field having magnitude E exists in positive x direction as shown in figure. The given two charged particles are released from rest at t=0 as shown in figure. If position of q1 at t=2 s is given by coordinate (+2a,0) then the x coordinate of q2 at t=2s is (neglect gravitational interaction between the particles) -

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Grade:11

1 Answers

Suresh
44 Points
2 years ago
(-2a,0) because same mass so particles have same acceleration . And because net force on system is 0 , so momentum is conserved . m1v1=m2v2 or m1x1 =m2x2

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