Two identical pith balls,each carrying a charge q,are suspended from a common point by two strings of equal length l1 &l2.find the mass of each ball if the angle between the strings is 2a in equilibrium.

Question

Arun · Answer

Dear Nikhil

Let the lengths of the two strings be equal to 'L'
The distance between the two pith balls will be, r = 2Lsinθ
now, here
electrostatic force = gravitational force
kq2/r2 = mgtanθ
or
kq2 / (2Lsinθ)2 = mgtanθ
or
m = kq2 / gtanθ(2Lsinθ)2
thus,
mass of each ball will be
m = kcosθq2 / 4gL2(sinθ)3

Regards
Arun (askIITians forum expert)

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Two identical pith balls,each carrying a charge q,are suspended from a common point by two strings of equal length l1 &l2.find the mass of each ball if the angle between the strings is 2a in equilibrium.

Two identical pith balls,each carrying a charge q,are suspended from a common point by two strings of equal length l1 &l2.find the mass of each ball if the angle between the strings is 2a in equilibrium.

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Two identical pith balls,each carrying a charge q,are suspended from a common point by two strings of equal length l1 &l2.find the mass of each ball if the angle between the strings is 2a in equilibrium.

Two identical pith balls,each carrying a charge q,are suspended from a common point by two strings of equal length l1 &l2.find the mass of each ball if the angle between the strings is 2a in equilibrium.

1 Answers

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