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`        . The length of a given cylindrical wire is increased by 100%  Due to the consequent decrease in diameter the change in the resistance of the wire will be (a) 200%(b) 100%(c) 50%(d) 300%`
6 years ago

bharat bajaj
IIT Delhi
122 Points
```							As we knowR = p L/ANew l` = 2l ..Due to increase in length, area must decrease as volume remains constant..Al = A`l` Hence, A` = A/2 New Resistance R` = pl`/A` = 4pl/AChange in resistance = 3pl/A or 300 %D) is the answerTHanksBharat BajajIIT Delhiaskiitians faculty
```
6 years ago
Navjyot Kalra
654 Points
```

(d) The total volume remains the
same before and after stretching.

Therefore A x l = A’ x l’

Here
l’ = 2 l

A’
= A x l / l’ = A x l / 2 l = A/2

Percentage
change in resistance

=
Rf – Ri / Rl x 100 = ? l’/A’ - l/A / l ? l/A x
100

=
[ (l’/A’ x A/ l) – 1 ] x 100 [(2 l/A/2
x A / l)-1 ] x 100

=
300%

```
6 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions