0

Guest

Courses New

the excess(equal in no) of electrons that must be placed on each of two spheres spaced 3 cm apart, with force of repulsion between sphere to be 10*-19 is

the excess(equal in no) of electrons that must be placed on each of two spheres spaced 3 cm apart, with force of repulsion between sphere to be 10*-19 is

Grade:12

1 Answers

Arun
25750 Points
5 years ago
 

Dear pallavi

let the charge on spheres is q

so F= 1/4∏ε qq/.032

  given F= 10-19

       1/4∏ε qq/.032 =10-19

 9 *109 * q2 /.032 =10-19 

               q=10-16

1 electron has  1.6 * 10-19 C  

 ne =q

 n=q/e =10-16/1.6 * 10-19 C

           =625

 

Regards

Arun

Think You Can Provide A Better Answer ?

Other Related Questions on Electrostatics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More