How to solve the following problem:
Very large rod, with constant longitudinal charge density Q’, is set in vacuum parallel to very large conductive ribbon with width ‘a’ , where height between them is ‘a/2’ . If the surface charge density of a ribbon is ‘s‘, calculate longitudinal force on a rod.

Thanks for reply.

Question

How to solve the following problem:
Very large rod, with constant longitudinal charge density Q’, is set in vacuum parallel to very large conductive ribbon with width ‘a’ , where height between them is ‘a/2’ . If the surface charge density of a ribbon is ‘s‘, calculate longitudinal force on a rod.

Thanks for reply.

Nicho priyatham · Answer

by integration is it force per unit length.....?

Nicho priyatham · Answer

is it QS/4e 0 ....?

Nemanja Grubor · Answer

@Nicho priyatham Yes, it is correct. Could you show the steps? Thanks.

Nemanja Grubor · Answer

@Nicho priyatham Here is what I did, but get wrong result. If we define electric field on y-axis (on the right side of ribbon) as dE y =cos(w)(sdl/2pie 0 r, where ‘w’ is angle between dE y and dE So, E y is the resultant field of a ribbon. When I integrate it, I get Ey=s/e 0 pi which is not correct. Also in my solution it says E y =(s/pie 0 )arctg(1) which is indeed E y =s/(4e 0 ). Now, F ‘ =Q ‘ E y =Q ‘ s/(4e 0 )

Nemanja Grubor · Answer

@Nicho priyatham Ok, I solved it.

Nicho priyatham · Answer

dats good nemanja sorry i was feeling lazy to type the solution i think u got it now if still any doubt i will definetly say u can i no what book u r using n wh clg ur in …..?

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