Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Derive the maximum value and position of electric field intensity on axis of uniformly charged ring. Note :Use the parameters given in attachment. What is know is d`dx E is 0.

Derive the maximum value and position of electric field intensity on axis of uniformly charged ring. Note :Use the parameters given in attachment. What is know is d`dx E is 0.

Question Image
Grade:12

1 Answers

ROSHAN MUJEEB
askIITians Faculty 829 Points
one year ago
Dear Student
Please find the expression of electric field . Use the concept of maxima and minima and to find maximum value . The distance comes out to be R/ root 2. Substitute this in original expression to max value . Hope you got it632-471_F8E2346D-6ECC-4DB6-81A3-0B4179E4E274.jpeg

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free