Question no.39Please help me to solve this problem
Sanjivani Shekhawat , 3 Years ago
Grade 12th pass
Electrostatics> Question no.39 Please help me to solve th...
2 AnswersAmlan Panigrahi
Last Activity: 3 Years ago
q=ne where q=charge acquired , n=no. of e- , e=charge of 1 e- (-1.6*10^-19 C)
so q=10^20 * -1.6*10^-19=-16C
that implies net charge=-16+5=-11c
Adarsh Srivastava
Last Activity: 2 Years ago
Using q=ne, q is the charge on body, n is the no of particles and e is the of 1 e-
Q=-1.6×10^-19×10^20
=-16C
So net charge=-16+5=11C
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Enter text here...
Other Related Questions on Electrostatics
Electrostatics question based on earthing of spherical shell
Electrostatics
0 Answer Available
Last Activity: 2 Year ago(s)
an object has a charge of 2c and gains 10^19 electrons. the net chaarge on the object becomes??
Electrostatics
1 Answer Available
Last Activity: 2 Year ago(s)
A wire with a linear charge density lambda forms a quarter of a cjrclenof radius R and is placed asa shown in thefigure with its centre of curvature at the origin O the electric field at O will be
Electrostatics
0 Answer Available
Last Activity: 2 Year ago(s)
Find the value of q so that system remains in equilibrium.. figure attached below
Electrostatics
0 Answer Available
Last Activity: 2 Year ago(s)
Find the value of q so that system remains in equilibrium
Electrostatics
0 Answer Available
Last Activity: 2 Year ago(s)