Flag Electrostatics> . A tiny electric dipole of dipole moment...
question mark

. A tiny electric dipole of dipole moment p k is placed at the origin. The electric fields at two far away point (b,0,0) and (0,0,b) are a) equal in magnitude b) equal c) equal in direction only d) unequal in magnitude and opposite in direction

Madhukar Anand , 11 Years ago
Grade
anser 1 Answers
Askiitians Tutor Team

Last Activity: 4 Months ago

To analyze the electric field generated by a tiny electric dipole at two far-off points, we need to consider the dipole moment and the nature of the electric field it produces. An electric dipole consists of two equal and opposite charges separated by a small distance, and its dipole moment \( \mathbf{p} \) is defined as the product of the charge and the distance between them, directed from the negative to the positive charge.

Understanding the Electric Field of a Dipole

The electric field \( \mathbf{E} \) due to a dipole at a point in space can be expressed in spherical coordinates, particularly when the point is far away from the dipole. The formula for the electric field at a distance \( r \) from the dipole is given by:

\[ \mathbf{E} \approx \frac{1}{4\pi \epsilon_0} \cdot \frac{2\mathbf{p} \cos \theta}{r^3} \]

Here, \( \theta \) is the angle between the dipole moment vector and the line connecting the dipole to the point where the field is being calculated, and \( \epsilon_0 \) is the permittivity of free space.

Evaluating the Electric Fields at the Given Points

Now, let's evaluate the electric fields at the two specified points: \( (b, 0, 0) \) and \( (0, 0, b) \).

  • Point (b, 0, 0): Here, the angle \( \theta \) between the dipole moment \( \mathbf{p} \) (which we can assume is along the z-axis for simplicity) and the x-axis is \( 90^\circ \). Thus, \( \cos(90^\circ) = 0 \). Therefore, the electric field at this point is:
  • \[ \mathbf{E}_{(b,0,0)} = 0 \]

  • Point (0, 0, b): At this point, the angle \( \theta \) is \( 0^\circ \) since the dipole moment is aligned with the z-axis. Thus, \( \cos(0^\circ) = 1 \). The electric field at this point is:
  • \[ \mathbf{E}_{(0,0,b)} = \frac{1}{4\pi \epsilon_0} \cdot \frac{2\mathbf{p}}{b^3} \]

Comparing the Electric Fields

From the calculations above, we see that:

  • The electric field at point \( (b, 0, 0) \) is zero.
  • The electric field at point \( (0, 0, b) \) has a non-zero magnitude and is directed along the z-axis.

Thus, the two electric fields are not equal in magnitude, nor are they equal in direction. In fact, one of them is zero while the other has a specific value. Therefore, the correct answer to the question is:

d) unequal in magnitude and opposite in direction

Conclusion

This analysis illustrates how the orientation of the dipole and the position of the observation points significantly affect the electric field's characteristics. Understanding these principles is crucial in fields like electrostatics and electromagnetism, where the behavior of electric fields is foundational.

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments