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(a, c) Let Q he the charge on the ring, the negative charge – q is released from point P (0, 0,Zo). The electric field at P due to the charged ring will be along positive z-axis and its magnitude will be
E = 1/ 4pe0 QZ0/(R2 +Z20)3./2
Therefore, force on charge P will be towards centre as shown, and its magnitude is
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