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Grade: 12
        
a particle of mass m and charge q is thrown with u velocity at an angle theta with the horizontal . if in space an electric field of strenght e exists vertiacally downward direction. find the horizontal range of this projectile.
 
5 months ago

Answers : (1)

chetan jangir
57 Points
							
If we solve question with neglect gravity
It’s horizontal component of velocity will not change 
And we hnow in any normal projectile Range is R = v02 sin 2θ0/a here a is the acceleration in perpenidular direction here Eq/m as a=f/m  so replacing here R=u^{2}sin2\Theta /Eq/m
5 months ago
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