A large flat metal surface has a unA capacitor of capacitance C is charged to a potential difference V from a cell and then
disconnected from it. A charge +Q is now given to its positive plate. The potential difference
across the capacitor is now

Question

hirendra · Answer

Ans should be V+q/2C It is obvious that charge is going to increase so capacitance is also increase with result in increasing V . So do charge distribution and u will get the ans

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A large flat metal surface has a unA capacitor of capacitance C is charged to a potential difference V from a cell and then disconnected from it. A charge +Q is now given to its positive plate. The potential difference across the capacitor is now

A large flat metal surface has a unA capacitor of capacitance C is charged to a potential difference V from a cell and then
disconnected from it. A charge +Q is now given to its positive plate. The potential difference
across the capacitor is now

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A large flat metal surface has a unA capacitor of capacitance C is charged to a potential difference V from a cell and then disconnected from it. A charge +Q is now given to its positive plate. The potential difference across the capacitor is now

A large flat metal surface has a unA capacitor of capacitance C is charged to a potential difference V from a cell and thendisconnected from it. A charge +Q is now given to its positive plate. The potential differenceacross the capacitor is now

1 Answers

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A large flat metal surface has a unA capacitor of capacitance C is charged to a potential difference V from a cell and then
disconnected from it. A charge +Q is now given to its positive plate. The potential difference
across the capacitor is now