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A large flat metal surface has a unA capacitor of capacitance C is charged to a potential difference V from a cell and thendisconnected from it. A charge +Q is now given to its positive plate. The potential differenceacross the capacitor is now
Ans should be V+q/2C It is obvious that charge is going to increase so capacitance is also increase with result in increasing V .So do charge distribution and u will get the ans
Ans should be V+q/2C
It is obvious that charge is going to increase so capacitance is also increase with result in increasing V .
So do charge distribution and u will get the ans
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