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A large flat metal surface has a unA capacitor of capacitance C is charged to a potential difference V from a cell and then
disconnected from it. A charge +Q is now given to its positive plate. The potential difference
across the capacitor is now

vasanth kumar p l , 8 Years ago
Grade 12
anser 1 Answers
hirendra

Ans should be V+q/2C  

It is obvious that charge is going to increase so capacitance is also increase with result in increasing V .

So do charge distribution and u will get the ans

 

 

Last Activity: 8 Years ago
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