A capacitor of capacitance C is charged to a potential difference V from a cell and then disconnected from it . A charge +q is now given to its positive plate. the potential difference across the capacitor is

Question

Khimraj · Answer

initial condition Q = CV V = Q/C final condition charge will redistribute and plates have charge Q + q/2 and -Q – q/2 so now V = (Q + q/2)/C = Q/C + q/2C = V + q/2C Hope it clears.

Kushagra Madhukar · Answer

Dear student, Please find the attached solution to your question. Just after the cell is disconnected, the capicitor will have Q = CV V = Q/C When +q charge is given to positively charged plate, it will redistribute and the plates would acquire the charges Q + q/2 and -Q – q/2 respectively. Hence, The new potential difference across capacitor, V’ = (Q + q/2)/C = Q/C + q/2C = V + q/2C Hope it helps. Thanks and regards, Kushagra

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A capacitor of capacitance C is charged to a potential difference V from a cell and then disconnected from it . A charge +q is now given to its positive plate. the potential difference across the capacitor is

A capacitor of capacitance C is charged to a potential difference V from a cell and then disconnected from it . A charge +q is now given to its positive plate. the potential difference across the capacitor is

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