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Dear Kuldeep,
net in the y direction = 0Tcos41 - mg = 0Tcos41 = mg >>>>>>eq1Fnet in the x direction = 0Tsin41 - F = 0Tsin41 = F >>>>>>eq 2Now divide eq2 by eq1 to get:tan41 = F / mgF = (tan41)(mg)And that's the Coulomb force. Then after you find the Coulomb force, apply Coulomb's law and solve for the charges:F = kq^2 / r^2F is the force solved up above. k is 9x10^9. r is the distance between the balls which can be obtained through a little trig **hint, the .4m will be the hypotenuse of 1 triangle post separation**And then after plugging in the numbers, solve for q.For the next part of the question, just relate tension to the equation used to solve for the Coulomb force above.Tsin41 = Coulomb ForceT = F / sin41
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