Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Two charges equal in magnitude and opposite in polarity are placed at certain distance apart and force acting between them is F. If 75 % charge of one is transferred to another, then the force between charges becomes

Two charges equal in magnitude and opposite in polarity are placed at certain distance apart and force acting between them is F. If 75 % charge of one is transferred to another, then the force between charges becomes

Grade:12

1 Answers

Khimraj
3007 Points
4 years ago
Just write the expression and then compareF= Kq(-q)/r²Now q` = 1/4qAnd -q`= -1/4qF` = k(q/4)(-q/4)/r²F` = F/16

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free