a conducting rod AB of length l falls vertically under gravity in a region of uniform magnetic field B.the field vectors are inclined at an angle k with the horizontal.if the instantaneous velocity of the rod is v the induced emf in the rod AB is

ans:0

a semicircular conducting ring acb of radius r moves with a constant speed v horizontally in a plane perpendicular to uniform magnetic field B.then

A)Va-Vc=Brv B)Vb-Vc=Brv

C)Va-Vb=0

ans:Va-Vb=0

Dear Harini,

Since the force exerted on the pts A and B of the semicircular ring is in the drection perpendicular to the direction of the velocity thats why Va -Vb =0

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