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a conducting rod AB of length l falls vertically under gravity in a region of uniform magnetic field B .the field vectors are inclined at an angle k with the horizontal.if the instantaneous velocity of the rod is v the induced emf in the rod AB is ans:0 a semicircular conducting ring acb of radius r moves with a constant speed v horizontally in a plane perpendicular to uniform magnetic field B.then A)Va-Vc=Brv B)Vb-Vc=Brv C)Va-Vb=0 ans:Va-Vb=0

a conducting rod AB of length l falls vertically under gravity  in a region of uniform magnetic field B.the field vectors are inclined at an angle k with the horizontal.if the instantaneous velocity of the rod is v the induced emf in the rod AB is


 


 


ans:0


 


 


 


a semicircular conducting ring acb of radius r moves with a constant speed v horizontally in a plane perpendicular to uniform magnetic field B.then


 


A)Va-Vc=Brv                           B)Vb-Vc=Brv


 


C)Va-Vb=0


 


ans:Va-Vb=0


 

Grade:11

1 Answers

Aman Bansal
592 Points
9 years ago

Dear Harini,

Since the force exerted on the pts A and B of the semicircular ring is in the drection perpendicular to the direction of the velocity thats why Va -Vb =0

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