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a conducting rod AB of length l falls vertically under gravity in a region of uniform magnetic field B.the field vectors are inclined at an angle k with the horizontal.if the instantaneous velocity of the rod is v the induced emf in the rod AB is
ans:0
a semicircular conducting ring acb of radius r moves with a constant speed v horizontally in a plane perpendicular to uniform magnetic field B.then
A)Va-Vc=Brv B)Vb-Vc=Brv
C)Va-Vb=0
ans:Va-Vb=0
Dear Harini,
Since the force exerted on the pts A and B of the semicircular ring is in the drection perpendicular to the direction of the velocity thats why Va -Vb =0
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