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`        Two identical cells of EMF 1.5v each joined in series supplied to external circuit of 17ohm each joined in parallel. Terminal resistance of cells is 1.4 v calculate internal resistance`
9 months ago

## Answers : (1)

```							Let r is the internal resistance of cell , E is the emf of cell. two cell of emf 1.5V and resistance r are in parallel also two resistors are joined in parallel with it as shown in figure. Terminal voltage of the = 1.4V is given . Means voltage ( V) = 1.4V are given voltage between two resistance which are joined in parallel with circuit .Now, we have to find out equivalent resistance, first find equivalent resistance of two given resistors,Req = R × R/(R + R) = R/2 = 17Ω/2 = 8.5Ω now, solve the circuit by applying Kirchoff's law , Let i current flow through the circuit also i₁ and i₂ Current flow through each emf.For first loop [ assume any loop in both ]iReq + i₁r - E = 0 i₁ = (E - iReq)/r ----(1)For second loop iReq + i₂r - E = 0 i₂ = ( E - iReq)/r now, I = i₁ + i₂ = (2E - 2iReq)/r ir =2E - 2iReq i = E/(Req + r/2) Also V = iReqI = V/Req = E/(Req + r/2) Now, put V = 1.4V , E = 1.5V , Req = 8.5Ω1.4/8.5 = 1.5/(8.5 + r/2) 1.4(8.5 + r/2) = 1.5 × 8.5 r = 1.21 ΩHence, answer is 1.21 Ω
```
9 months ago
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