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The length of a given cylindrical wire is increased by 100% due to the consequent decrease in diameter the change in the resistance of the wire will be
As we knowR = p L/ANew l` = 2l ..Due to increase in length, area must decrease as volume remains constant..Al = A`l`Hence, A` = A/2New Resistance R` = pl`/A` = 4pl/AChange in resistance = 3pl/A or 300 %
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