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n identical cells , each of emf E and internal resistance r , are joined in series to form a closed circuit. one of the cell A is joined with reversed polarity the potential difference across each cell except A is :- plzz give proper solution with detail explanation plzzzzzzzzzzzzz
I = (ne- 2e)/nr I = (n-2)e/nr As we know V = e - Ir V = e - (n -2)e/n V = (ne - ne +2e)/n V = 2e/n Hope you got the answer
Dear student,Please find the attached solution to the question. The potential drop across circuit, V = (n – 1)E – E = (n – 2)ECurrent flowing in the circuit, I = (n – 2)E/nrHence potential drop across each cell (except A), V’ = E – Ir = E – (n – 2)E/n = 2E/nHope it helps.Thanks and regards,Kushagra
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