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The figure here shows a portion of a circuit. What are the magnitude and direction of the current ‘i’ in the lower right hand-wire ?

KRUNAL THUMAR , 4 Years ago
Grade 12
anser 1 Answers
Antara

Last Activity: 4 Years ago

Apply kirchoffs current law at each junction of the circuit. i.e. current going in=current coming out.
See from left....2A+3A=5A (--> direction)
then 1A+2A=3A (upward dirn)
then 5A-3A=2A (downward dirn)
then 4A+2A=6A (rightward dirn)
then 6A+2A=8A=i (rightward dirn)............ans
 
Hope it helps :))

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