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Here is the question: Two springs are connected as in the figure. F 1 = -k 1 x 2 and F 2 = -k 2 x. Let AB = l, rod is massless. Force F is applied at O. AO = y. Find the equivalent spring constant for 0 Please explain what exactly is meant by equivalent spring constant here, and how to find it.


Here is the question:

 Two springs are connected as in the figure. F1 = -k1x2 and F2 = -k2x. Let AB = l, rod is massless. Force F is applied at O. AO = y.

Find the equivalent spring constant for 0 < x <<1 (small displacement).

 

Please explain what exactly is meant by equivalent spring constant here, and how to find it. 


Grade:upto college level

1 Answers

Saurabh Kumar
askIITians Faculty 2411 Points
6 years ago
since, 1. Diagram is missing.
2. F1 is directly proportional to the square of the displacement, which is not obeyed according to Hooke’s law.
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