A thick spherical shell has inner radius a and outer b, the material has resistivity r. when a potential difference is applied between the inner & outer surfaces, its resistance is?

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Khimraj · Answer

We assume a shell element of thickness dp and of radius p. then resistance is given by dR = rdp/4 πp 2 R = (r/4π) dp/p 2 = (r/4π)(1/a – 1/b). Hope it clears. If you like anser then please approve it.

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A thick spherical shell has inner radius a and outer b, the material has resistivity r. when a potential difference is applied between the inner & outer surfaces, its resistance is?

A thick spherical shell has inner radius a and outer b, the material has resistivity r. when a potential difference is applied between the inner & outer surfaces, its resistance is?

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A thick spherical shell has inner radius a and outer b, the material has resistivity r. when a potential difference is applied between the inner & outer surfaces, its resistance is?

A thick spherical shell has inner radius a and outer b, the material has resistivity r. when a potential difference is applied between the inner & outer surfaces, its resistance is?

1 Answers

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