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A potentiometer wire 10m long and having 20 Ω resistance is connected in series with a battery and a resistance R = 2160 Ω . A Daniel cell of emf 1.08 v is balanced across the P.D. of the resistance R. The emf of thermo couple is balanced across 300 cm of the wire. The emf of thermo couple is

Archit Archyut , 8 Years ago

Grade 12th pass

1 Answers

Eshan

Last Activity: 7 Years ago

Current through the potentiometer wire= $i=\dfrac{E}{20+2160}$

Hence potetial difference across the potentiometer wire= $(\dfrac{E}{20+2160})(20)$
Therefore, emf of thermocouple=potential difference over 3m length of wire= $\dfrac{3}{10}\times(\dfrac{E}{20+2160})(20)$ =3mV

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