One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM

DETAILS

MRP

DISCOUNT

FINAL PRICE

Total Price: Rs.

There are no items in this cart.

Continue Shopping

Continue Shopping

3 years ago

SInce the angle subtended is 60 degrees at the apex and both the sides are equal in length, the top of the letter A will make an equilateral triangle. hence all the three sides will be 10 3 cm each and correspondingly will have a resistance of 3 ohms each.

The top triangle in A can be considered as 2 resistors of 3 ohms in series and 1 resistor of 3 ohm in parallel. Effective resistance of this traingle becomes 6/3 = 2 ohms. Now the effective circuit is 3 resistors of 3, 2 and 3 in series. Hence effective resistance is 8 = 8 ohms

Regards

Arun (askIITians forum expert)

2 years ago

SInce the angle subtended is 60 degrees at the apex and both the sides are equal in length, the top of the letter A will make an equilateral triangle. hence all the three sides will be 10 3 cm each and correspondingly will have a resistance of 3 ohms each.The top triangle in A can be considered as 2 resistors of 3 ohms in series and 1 resistor of 3 ohm in parallel. Effective resistance of this traingle becomes 6/3 = 2 ohms. Now the effective circuit is 3 resistors of 3, 2 and 3 in series. Hence effective resistance is 8 = 8 ohms

9 months ago

Since the angle of the apex is 60, that means the other two angles are also 60 and this is an equilateral triangle. That means the length from the apex to the cross side is the same as the cross side = 10cm which is 1ohm/cm * 10cm = 10 ohm. Thus the other wire from the apex to the other side of the cross side is also 10 ohm. Thus the wire in parallel with the cross side is 10+10 = 20 ohms.

The cross side is 10cm * 1 ohm/cm = 10 ohm

10 ohms in parallel with 20 ohms: 10||20 = 200/30 = 20/3 ohms.

The resistance of each leg to the cross side is then 10cm * 1 ohm/cm = 10 ohms. So the total resistance seen from the legs is 10 + 20/3 + 10 = 80/3 ohms = 26 and 2/3 ohms = 26.67 ohm

The cross side is 10cm * 1 ohm/cm = 10 ohm

10 ohms in parallel with 20 ohms: 10||20 = 200/30 = 20/3 ohms.

The resistance of each leg to the cross side is then 10cm * 1 ohm/cm = 10 ohms. So the total resistance seen from the legs is 10 + 20/3 + 10 = 80/3 ohms = 26 and 2/3 ohms = 26.67 ohm

copyright © 2006-2021 askIITians.com

info@askiitians.com