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Grade: 11

                        

The electric flux f through a hemisphere surface of radius R, placed in a uniform electric field of intensity E parallel to the axis of its circular plane is: (a) 2 p RE (b) 2 pR2E (c) pR2E (d) (4/3) pR3E

8 years ago

Answers : (3)

Anirban Mukherjee
47 Points
							

Electric Flux through any surface

= Electric field Intensity at the surface

´ component of surface ^

to direction of electric Field

=EΠR2

8 years ago
Sharandeep singh
15 Points
							

since it is placed in uniform e field therefore net charge enclosed is 0 and therefore net flux is zero

i.e. flux through circular part + flux through hemi spherical part = 0

flux through circular part = - flux through hemi spherical part

                                   = e * 2pr^2 ( area of hemisphere = 1/2*4pr^2 = 2pR^2 )

hence b is correct

7 years ago
Kushagra Madhukar
askIITians Faculty
605 Points
							
Dear student,
Please find the solution to your question below.
 
Electric Flux through any surface = Electric field Intensity at the surface x component of surface perpendicular to direction of electric Field = EΠR2
 
Hope it helps.
Thanks and regards,
Kushagra
3 months ago
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