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The electric flux f through a hemisphere surface of radius R, placed in a uniform electric field of intensity
E parallel to the axis of its circular plane is:
(a) 2 p RE (b) 2 pR2E (c) pR2E (d) (4/3) pR3E
Electric Flux through any surface = Electric field Intensity at the surface
Electric Flux through any surface
= Electric field Intensity at the surface
´ component of surface ^
to direction of electric Field =EΠR2
=EΠR2
since it is placed in uniform e field therefore net charge enclosed is 0 and therefore net flux is zero
i.e. flux through circular part + flux through hemi spherical part = 0
flux through circular part = - flux through hemi spherical part
= e * 2pr^2 ( area of hemisphere = 1/2*4pr^2 = 2pR^2 )
hence b is correct
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