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12 cell each having the same e.m.f are cannected in series and are kept in a closed box. Some of the cell are wrongly connected. This battery is connected in series with an ammeter and the two cells identical with the other the current is 3A when the cells and battery aid each other and is 2A when the cells and battery oppose each other .How many cell are wrongly connected?
12 cell each having the same e.m.f are cannected in series and are kept in a closed box. Some of the cell are wrongly connected. This battery is connected in series with an ammeter and the two cells identical with the other the current is 3A when the cells and battery aid each other and is 2A when the cells and battery oppose each other .How many cell are wrongly connected?

```
3 years ago

## Answers : (1)

Raj Ranjan
38 Points
```							Let there be ‘n’ cells with opposite polarity inside the battery,
so p.d. across the battery is  (12-n)E-nE= (12-2n)E.
A/Q, (12-2n)E+2E=3R  ---(i) {R is the net resistance of the cuircuit}
(12-2n)E-2E=2R         --(ii)
(i)/(ii) we get,
(14-2n)/(10-2n)=3/2
=>28-4n=30-6n
=>2n=2
=>n=1
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions