0

Guest

Courses New

12 cell each having the same e.m.f are cannected in series and are kept in a closed box. Some of the cell are wrongly connected. This battery is connected in series with an ammeter and the two cells identical with the other the current is 3A when the cells and battery aid each other and is 2A when the cells and battery oppose each other .How many cell are wrongly connected?

12 cell each having the same e.m.f are cannected in series and are kept in a closed box. Some of the cell are wrongly connected. This battery is connected in series with an ammeter and the two cells identical with the other the current is 3A when the cells and battery aid each other and is 2A when the cells and battery oppose each other .How many cell are wrongly connected?

Grade:11

1 Answers

Raj Ranjan
38 Points
6 years ago
Let there be ‘n’ cells with opposite polarity inside the battery,
so p.d. across the battery is  (12-n)E-nE= (12-2n)E.
A/Q, (12-2n)E+2E=3R  ---(i) {R is the net resistance of the cuircuit}
(12-2n)E-2E=2R         --(ii)
(i)/(ii) we get,
(14-2n)/(10-2n)=3/2
=>28-4n=30-6n
=>2n=2
=>n=1

Think You Can Provide A Better Answer ?

Other Related Questions on Electric Current

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More