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if a+3b+2c=12 than minimum value of 6bc(1+a)+a(3b+2c) if a,b,c belongs to R if a+3b+2c=12 than minimum value of 6bc(1+a)+a(3b+2c) if a,b,c belongs to R
HiiIt can be done by taking acombinatio of alphabets in the order in which they are appearing . You can use 12-a= 3b + 2c. From there you will get quadratic and you can use quadratic inequality to get the answer
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