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`        A massless spring of length l and spring constant k is placed vertically on a table. A ball of mass m is just kept on top of the spring. What is the maximum velocity of the ball?`
9 months ago

Snehita
14 Points
```							Equation for net force acting on the ball:ma=mg – kx …............(1)(where a => acceleration of the ball)wkt a = dv/dt    (i.e. rate of change of velocity,v with respect to time,t )=> a = (dv/dx)*(dx/dt) but dx/dt = v=> a = v(dv/dx)For velocity to be maximum , dv/dx = 0 …..............(2)From (1) & (2) => m*0 = mg – kx=> x = mg/k …...............(3)Now , from conservation of energy ,=> 1/2(mv^2) = 1/2(kx^2)Substitute (3)=> mv^2 = k(m^2 g^2)/k^2=> v=g(m/k)^1/2
```
9 months ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions