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A goods train completely crosses a 120 m long bridge with uniform speed 'v' in 't' seconds. Then it will cross 240 m long bridge with uniform speed 2v in.
T = distance/speed = 120/v (initial time) final time = 240/2v = 120/v (final time) therefore time will remain same ......
T = distance/speed = 120/v (initial time)
final time = 240/2v = 120/v (final time)
therefore time will remain same ......
We know, s=ut+1/2 at2 but since the train is going with uniform velocity, hence the acceleration is zero. therefore, s=ut In the first case, 120=vt t=120/v In the second case, 240=2vt t=120/v Hence, the time in both the cases, time taken will be the same. Please Approve!!
We know,
s=ut+1/2 at2
but since the train is going with uniform velocity, hence the acceleration is zero.
therefore,
s=ut
In the first case,
120=vt
t=120/v
In the second case,
240=2vt
Hence, the time in both the cases, time taken will be the same.
Please Approve!!
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