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Grade: 12
        a horizontal rod of mass m is hinged at 1end and the other end is conected to a vertical spring wth spring cnstant k..whn system is at eq. find the potential energy f the spring
7 years ago

Answers : (1)

Sukhendra Reddy Rompally B.Tech Mining Machinery Engg, ISM Dhanbad
93 Points
							

Hello!

Balancing the moments about the hinged end,you get mgl/2 = kxl ( since,weight at the centre of mass is mg and force at the other end is kx}

from this,you get x=mg/2k

now Potential energy of spring is 0.5kx^2,substituting the value of k,we get

potential energy of spring = (mg)^2/8k

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7 years ago
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