A man running on a horizontal road at 8km/hr finds the rain falling vertically. He increases his speed to 12km/hr and finds that the rain drops make an angle of 30 with the vertical.Find the speed and direction of the rain with respect to the road.

Question

Harshit Singh · Answer

Dear Student

This shows that the horizontal component of rain=8km/hras the relative velocity of the rain has only a vertical component with respect the man.
Vx=8km/hr
2ndcase
→VRM=VR−VM
=(8↑−Vy↑)−12↑
=−4↑−V_y↑
tan30^o= 4 /V_y
⇒ 1 / √3 = 4 /Vy
Vy = 4√3km/hr

Velocity of Rain= 8km/hr↑−4√3km/hr↑
⇒tan α = 2 / √3 from vertical.

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A man running on a horizontal road at 8km/hr finds the rain falling vertically. He increases his speed to 12km/hr and finds that the rain drops make an angle of 30 with the vertical.Find the speed and direction of the rain with respect to the road.

A man running on a horizontal road at 8km/hr finds the rain falling vertically. He increases his speed to 12km/hr and finds that the rain drops make an angle of 30 with the vertical.Find the speed and direction of the rain with respect to the road.

A man running on a horizontal road at 8km/hr finds the rain falling vertically. He increases his speed to 12km/hr and finds that the rain drops make an angle of 30 with the vertical.Find the speed and direction of the rain with respect to the road.

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