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# If (1+x)n=C0+C1x+C2x2....+Cnxn,thenC0+3C1+5C2+...+(2n+1)Cn  is equal to(a)n*2n(b)(n+1)2n(c)n*2n+1(d)0

12 years ago

hi vaibhav,

solve this problem using the same trick,put n=2

(1+x)=1+2x+x,so c0=1,c1=2,c2=1

c0+3c1+5c2=12,now solve all the options with n=2 u'll find option(b)(n+1)2n=12 is the right answer.

12 years ago

hi vaibhav,

in dis problem , u can write d general term of d series dat u hav to find,

Tr = (2r + 1)Cr

now apply summation ,

S =2 *  sum r* Cr + sum Cr

sum Cr can be calculated by putting 1 in place of x in (1+x)^n, dat will give 2^n

for r * Cr , u just differentiate (1+x)^n  and again put 1 in place of x , den u will get n*2^(n-1)=C1+2*C2+.......

d final expression after adding will be n*2^n +2^n = (n+1)2^n