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```
What is iota^iota . I really needed to know this so my friend told me that ask the iitians . So i am asking an iitian , hopefully you will answer my question ASAP thanks

```
4 years ago

SAHIL
3783 Points
```							Iota is a complex number with the value of root under -1 , so iota to the power iota is , root under -1 to the power root under -1.THANKSPOST IF ANY QUERY OR DOUBT
```
4 years ago
krunal
52 Points
```							actually the ans is (-pie/2).here, lets assume that A=i^i. taking log on both side, we can write> logA =ilogilogA=ilog(1i)......logA=i[ log1+logi]...........by logarithm propertylogA=I[0+i(PIE/2)]......(ARG OF i=pie by 2)on soloving we get logA=(-PIE/2)THEREFORE A=e^(-pie/2)
```
4 years ago
Umakant biswal
5359 Points
```							@ lvanish iota is besically a greek letter which is used to define the imaginary part of a complex number lets say we have an equation x^2 +1 =0 the value of x will be the square root of -1 which is fundamentally not possible . to solve such equation u need the square root of some negative number ,. the concept of complex number are introduced for that . iota is used to denote the square root of -1 . some books u will find that iota is a number whoose square is -1 ..
```
4 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions