SAGAR SINGH - IIT DELHI
Last Activity: 13 Years ago
Dear student,
I will give u a hint here:
Expansion (x+y)n :
(i) There are (n+1) terms in the expansion.
(ii) In each term, sum of the indices of ‘x’ and ‘y’ is equal to ‘n’.
(iii) In any term, the lower suffix of ‘c’ is equal to the index of ‘y’, and the index of x = n-(lower suffix of c).
(iv) Because nCr = nCn-r,
so we have :
nCo = nCn
nC1=nCn-1
nC2=nCn-2 etc.
It follows that the coefficients of terms equidistant from the beginning and the ends are equal.
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
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Sagar Singh
B.Tech, IIT Delhi
sagarsingh24.iitd@gmail.com