two masses M1=1 kg and M2=2 kg are connected by a mass less spring. a force of 4N acts on the 2kg mass. what will be accn of M2 if accn of M1 is 1m/s^2

85 Points
11 years ago

Dear Zahid,

FOr M1 : eq of motion -       M1 a1 = kx or kx = 1 N

For M2 : eq of motion  -     F - kx = M2a2

or  4 - 1 = 2 a2

a2 = 3/2 m/s2

All the best.

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Anil pannikar

IIT Bombay

105 Points
11 years ago

Dear Zahid,

considering the free body diagram of M2,forces in it are,

F-Fspring = M2*a

on mass M1 ,forces in horizintal direction are

Fspring = M1*a1

Given s1 = 1 m/s^2

Hence Fspring = 1 N

M2*s2 = Fgiven - F spring

M2*s2 = 4 - 1 = 3 N

Hence accelaration of the MASS M2 = 1.5 m/s^2

All the best.

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