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see attachment and explain it

Shivam , 10 Years ago
Grade 12
anser 1 Answers
Arun Kumar

Last Activity: 10 Years ago

Hello

if f=x^alpha *sin(1/x) at x not equal to zero.
then
by squeeze theorem limit x to 0 f will be = 0 for alpha > 0
but randomness around 0 is too great for alpha=1 so not differentiable.
so alpha > 1
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
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