Please cansomeone answer this quickly The slope of the tangent to the curve at a point (x,y) on it is proportional to (x-2). If the slope of the tangent to the curve at (10, 9) on it is -3. The equation of the curve is Ans. y = (-3/16) (x-2) 2 + 3

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Please cansomeone answer this quickly The slope of the tangent to the curve at a point (x,y) on it is proportional to (x-2). If the slope of the tangent to the curve at (10, 9) on it is -3. The equation of the curve is Ans. y = (-3/16) (x-2) 2 + 3

Please cansomeone answer this quickly

The slope of the tangent to the curve at a point (x,y) on it is proportional to (x-2). If the slope of the tangent to the curve at (10, 9) on it is -3. The equation of the curve is
Ans. y = (-3/16) (x-2)² + 3

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Please cansomeone answer this quickly The slope of the tangent to the curve at a point (x,y) on it is proportional to (x-2). If the slope of the tangent to the curve at (10, 9) on it is -3. The equation of the curve is Ans. y = (-3/16) (x-2) 2 + 3

Please cansomeone answer this quickly The slope of the tangent to the curve at a point (x,y) on it is proportional to (x-2). If the slope of the tangent to the curve at (10, 9) on it is -3. The equation of the curve isAns. y = (-3/16) (x-2)2 + 3

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Please cansomeone answer this quickly

The slope of the tangent to the curve at a point (x,y) on it is proportional to (x-2). If the slope of the tangent to the curve at (10, 9) on it is -3. The equation of the curve is
Ans. y = (-3/16) (x-2)² + 3