If x=sint, y=ae t root 2 +be t root 2 ,t resembles (-pi/2,pi/2) satisfies the equation (1-x^2)d2y/dx2 -x.dy/dx=ky then find k. Answer =2.

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If x=sint, y=ae t root 2 +be t root 2 ,t resembles (-pi/2,pi/2) satisfies the equation (1-x^2)d2y/dx2 -x.dy/dx=ky then find k. Answer =2.

If x=sint, y=ae^{t root 2}+be^{t root 2},t resembles (-pi/2,pi/2) satisfies the equation (1-x^2)d2y/dx2 -x.dy/dx=ky then find k. Answer =2.

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If x=sint, y=ae t root 2 +be t root 2 ,t resembles (-pi/2,pi/2) satisfies the equation (1-x^2)d2y/dx2 -x.dy/dx=ky then find k. Answer =2.

If x=sint, y=aet root 2 +bet root 2 ,t resembles (-pi/2,pi/2) satisfies the equation (1-x^2)d2y/dx2 -x.dy/dx=ky then find k. Answer =2.

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If x=sint, y=ae^{t root 2}+be^{t root 2},t resembles (-pi/2,pi/2) satisfies the equation (1-x^2)d2y/dx2 -x.dy/dx=ky then find k. Answer =2.