If x=sint, y=aet root 2 +bet root 2 ,t resembles (-pi/2,pi/2) satisfies the equation (1-x^2)d2y/dx2 -x.dy/dx=ky then find k. Answer =2.
If x=sint, y=aet root 2 +bet root 2 ,t resembles (-pi/2,pi/2) satisfies the equation (1-x^2)d2y/dx2 -x.dy/dx=ky then find k. Answer =2.