If f(10=1, f(2n)=n and f(2n+1) = (f(n))^2 – 2 for n=1,2,..., then the value of f(1) + f(2) + … + f(25) =

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Sourabh Singh · Answer

Hii First separate odd n even terms. Even is simple to calculate Odd part willl again be sepated in odd n even . Apply the same procedure repeatedly .You will get the answer

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If f(10=1, f(2n)=n and f(2n+1) = (f(n))^2 – 2 for n=1,2,..., then the value of f(1) + f(2) + … + f(25) =

If f(10=1, f(2n)=n and f(2n+1) = (f(n))^2 – 2 for n=1,2,..., then the value of f(1) + f(2) + … + f(25) =

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If f(10=1, f(2n)=n and f(2n+1) = (f(n))^2 – 2 for n=1,2,..., then the value of f(1) + f(2) + … + f(25) =

If f(10=1, f(2n)=n and f(2n+1) = (f(n))^2 – 2 for n=1,2,..., then the value of f(1) + f(2) + … + f(25) =

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