# The orbital angular momentum of a p-electron is given as :a) $\dpi{100} \frac{h}{\sqrt2 \pi}$b) $\dpi{100} \sqrt 3 \frac{h}{2 \pi}$c) $\dpi{100} \sqrt\frac{3}{2} \frac{h}{\pi}$d) .$\dpi{100} \sqrt 6\frac{h}{2\pi}$

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## 1 Answers

Arun
25757 Points
3 years ago
Orbital angular momentum is given by root(l(l+1))*h/2pi where l is the azimuthal quantum no. and h is plank's constant

For p orbit , l=1

Orbital angular momentum = root(2)*h/2pi

Hence option A is correct.

Hope it helps