The foci of the hyerbola are S(-3,-2) and S`(5,6). If it`s e=2 then the equation of it`s directrix corresponding to focus S is

Question

Vikas TU · Answer

Dear Student,

a=-3/2

B^2 = a^2(1-e^2) = 3a^2 = 27/4

B= (3√3)/2

Point on directrix = (-2,3√3/2 ) ; slope of directrix = -1 (perpendicular to axis)

Equation : x+y+2-3√3/2 =0

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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The foci of the hyerbola are S(-3,-2) and S`(5,6). If it`s e=2 then the equation of it`s directrix corresponding to focus S is

The foci of the hyerbola are S(-3,-2) and S`(5,6). If it`s e=2 then the equation of it`s directrix corresponding to focus S is

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The foci of the hyerbola are S(-3,-2) and S`(5,6). If it`s e=2 then the equation of it`s directrix corresponding to focus S is

The foci of the hyerbola are S(-3,-2) and S`(5,6). If it`s e=2 then the equation of it`s directrix corresponding to focus S is

1 Answers

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