Grade 12Analytical GeometryThe foci of the hyerbola are S(-3,-2) and S`(5,6). If it`s e=2 then the equation of it`s directrix corresponding to focus S is Gopathi Dileepkumar 9 Years agoGrade 12
Vikas TU9 Years agoDear Student,a=-3/2B^2 = a^2(1-e^2) = 3a^2 = 27/4 B= (3√3)/2Point on directrix = (-2,3√3/2 ) ; slope of directrix = -1 (perpendicular to axis)Equation : x+y+2-3√3/2 =0 Cheers!!Regards,Vikas (B. Tech. 4th yearThapar University)