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Find the equation of the line which is at a perpendicular distance of 5 units from the origin and the angle made by the perpendicular with the positive x-axis is 30°. Find the equation of the line which is at a perpendicular distance of 5 units from theorigin and the angle made by the perpendicular with the positive x-axis is 30°.
Find the equation of the line which is at a perpendicular distance of 5 units from the
origin and the angle made by the perpendicular with the positive x-axis is 30°.
Welcome to AskiitiansIf p is the length of the normal from the origin to a line and ω is the angle made by thenormal with the positive direction of the x-axisThen, the equation of the line for the given condition is written byx cos ω + y sin ω = p.Here, p = 5 units and ω = 30°Thus, the required equation of the given line isx cos 30°+ y sin 30° = 5x(√3/2) + y(½) = 5It becomes√ 3x +y = 10Thus, the required equation of a line is √ 3x + y = 10Thanks
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